Current Announcements
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I have submitted the final course grades
(anonymous sorted list)
to the registrar.
The anonymous sorted grades for the final exam,
Final/sorted_grades.txt.
The anonymous sorted grades for the combined homeworks scaled to 20,
Homework/sorted_grades.txt.
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On request, solution to Homework 4, Problem 1:
(b0 + 5*b1 + 25*b2)^2 equiv 94 (mod 125). (*)
Then b0^2 equiv 4 (mod 5), so b0 = 2 or = 3. Take 2.
Then (2 + 5*b1)^2 equiv 94 (mod 25), reducing (*) modulo 25.
So 4 + 4*5*b1 equiv 19 (mod 25), or 20*b1 equiv 15 (mod 25).
That means that 4*b1 equiv 3 (mod 5) [note the division by 5]
or b1 = 2.
Thus (12 + 25*b3)^2 equiv 94 (mod 125) or 144 + 2*12*25*b3 equiv 94 (mod 125).
So 12*50*b2 equiv 94-19 equiv 75 (mod 125).
That means 12*2*b2 equiv 3 (mod 5) [note the division by 25]
or b3 = 2.
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The final exam is Wednesday, May 5, at 9am in our class room.
You may bring 3 sheets of notes.
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The course web sites for
Spring 2009,
Spring 2008,
Spring 2007
and
Spring 2005
contain old homeworks, mid-semester exams, and anonymous grade lists.
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My office hours are listed on my
schedule.
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